audioInputStream with Zip

Java Sound & OpenAL
#1

I’m currently trying to load a group of files from a single zip which inlcudes; images, text files, data files, wav files and anything else my little heart desires. The problem is that all the files that I recieve from the zip as a byte array, work fine - except for the wav files. If I load the wav file from a URL it works fine. The clip that gets created by the byte array appears to be a valid format. Oh and before anybody suggest putting the files into my jar - that is not an option. Here is the code that I’m using. And thanks for taking a look:

`
public void createClip( URL data ) //works
{

        AudioInputStream      audioInputStream = null;
                                
        try
        {
              audioInputStream = AudioSystem.getAudioInputStream( data );
        }
        catch (Exception e)
        {
              e.printStackTrace();
        }
        
        create( audioInputStream );
  }
  
  public void createClip( byte[] data ) //does not work
  {
        
        AudioInputStream      audioInputStream = null;      
                                      
        try
        {
              
              audioInputStream = AudioSystem.getAudioInputStream( new ByteArrayInputStream( data ) );
        }
        catch (Exception e)
        {
              e.printStackTrace();
        }
        create( audioInputStream );
  }      
  
  private void create( AudioInputStream audioInputStream )
  {
        if (audioInputStream != null)
        {
              AudioFormat      format = audioInputStream.getFormat();
              DataLine.Info      info = new DataLine.Info(Clip.class, format);
              try
              {
                    m_clip = (Clip) AudioSystem.getLine(info);
                    m_clip.addLineListener( this );      
                    m_clip.open(audioInputStream);
                    
              }
              catch (LineUnavailableException e)
              {
                    e.printStackTrace();
              }
              catch (IOException e)
              {
                    e.printStackTrace();
              }            
              m_clip.loop(100);      //just make it loop
        }
        else
        {
              System.out.println("bad audio file");
        }
        
  }

`

#2

Although it should not be a problem to create an AudioInputStream using byte array, you could create one even easier directly using ZipFile.getInputStream. Unless there is a specific reason why you need to use byte[] instread…

ZipFile zf = new ZipFile(“test.zip”);
Enumeration entries = zf.entries();

ZipEntry ze = (ZipEntry) entries.nextElement();
while(!ze.getName().equals(“music.wav”)) {
ze = (ZipEntry) entries.nextElement();
}

AudioInputStream audioInputStream = AudioSystem.getAudioInputStream(zf.getInputStream(ze));